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 Everyone Loves Someone
 Everyone Loves Someone
 There is one person everyone loves
 There is one person everyone loves
![$\forall x [P(x) \wedge Q(x)] = \forall x P(x) \wedge \forall x Q(x)$](img20.gif) 
 Distributes over AND only)
 Distributes over AND only)
![$\exists x [P(x) \vee Q(x)] = \exists x P(x) \vee \exists x Q(x)$](img22.gif) 
 Distributes over OR only)
 Distributes over OR only)
 where t is a term
 where t is a term
 
 
 
Sample Proof (using Universal Instantiation)
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|  | Modus Ponens |